solve linear-quadratic system algebraically. then what is the y-coordinate of the solution? show all work.

y = x^2 + 2x + 7
y – 7 = x

see explanation

Step-by-step explanation:

Given the 2 equations

y = x² + 2x + 7 → (1)

y - 7 = x → (2)

Rearrange (2) expressing y in terms of x by adding 7 to both sides

y = x + 7 → (3)

Substitute y = x + 7 into (1)

x + 7 = x² + 2x + 7 ( subtract x + 7 from both sides )

0 = x² + x ← factor out x from each term

0 = x(x + 1)

Equate each factor to zero and solve for x

x = 0

x + 1 = 0 ⇒ x = - 1

Substitute these values into (3) for corresponding values of y

x = 0 → y = 0 + 7 = 7

x = - 1 → y = - 1 + 7 = 6

The solutions are

(- 1, 6 ) and (0, 7 )

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph