Kevin and randy muise have a jar containing 55 coins, all of which are either quarters or nickels. the total value of the coins in the jar is $9.35 how many of each type of coin do they have?

The number of quarters in the jar  =   33

The number of nickels  = 22

Step-by-step explanation:

Let us assume the total number of quarters in the jar  = m

Now,as the total number of coins in the jar  = 55

SO, the number of nickels in the jar = 55 - m

Also, 1 quarter = $0.25

So, m quarters  = m  x ( $0.52) = $ 0.25 m   (1)

1 nickel = $0.05

So, (55 - m) nickels  = (55 - m)  x ( $0.05) = $ (2.75 - 0.05 m) (2)

Total Value in the jar = $9.35

⇒ The value of m quarters  +  (55 - m) nickels  = $9.35

or,  $ 0.25 m + $ (2.75 - 0.05 m)  = $9.35               from (1 and 2)

or,  0.25 m + 2.75 - 0.05 m =  9.35

⇒ 0.2 m =  6 .6

or, m  = 6.6/0.2 =  33

or, m = 33

Hence the number of quarters in the jar = m=  33

The number of nickels  = 55 - m = 55 -33 =22

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6