Which function's graph has a period of 2?
y=cos(x-pi/2)
y=3cos pi x
y=2 sin 3x
y=-4 sin 2x

Option 2. y = 3 cos πx is the answer.

Step-by-step explanation:

If the function is in the standard form of y = acos(bx+c)  or y = asin(bx+c)

Then period of the given function will be = 2π/b

1) For y = cos(x - π/2)

Therefore period of the function will be = 2π/1 = 2π

2) For y = 3cos πx

Period = 2π/π = 2

Correct option.

3) y = 2 sin 3x

Period of the function = 2π/3

4). y = -4sin 2x

Period of the function = 2π/2 = π

So option 2 is the answer.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct