(1 point) consider the two dimensional subspace uu of r3r3 spanned by the set {u1,u2}{u1,u2} where u1=⎡⎣⎢−12−1⎤⎦⎥,u2=⎡⎣⎢−2−10⎤⎦⎥. u1=[−12−1],u2=[−2−10]. the orthogonal complement v=u⊥v=u⊥ of uϵr3uϵr3 is the one dimensional subspace of r3r3 such that every vector vϵvvϵv is orthogonal to every vector uϵuuϵu. in other words, u⋅v=0u⋅v=0 for all uϵuuϵu and vϵvvϵv. find the first two components v1v1 and v2v2 of the vector vϵvvϵv for which v3=1v3=1.

linear

step-by-step explanation:

she drove 134 miles

step-by-step explanation:

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh