Water flows straight down from an open faucet. the cross-sectional area of the faucet is 1.00 × 10 − 4 m², and the speed of the water is 0.72 m/s as it leaves the faucet. ignoring air resistance, find the cross-sectional area of the water stream at a point 0.19 m below the faucet.

Step-by-step explanation:

Given

velocity

Area of cross-section

velocity after Falling 0.19 m

conserving Flow

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

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step-by-step explanation: