For the following system of equations what is the x - value of the solution. -x+2y=6 6y=x+18

For the system of equations given, x = 0

Step-by-step explanation:

1. Let's solve the system of equations to find out the value of x:

1st equation:

x+ 2y = 6

x = 6 - 2y (Subtracting 2y at both sides)

2nd equation:

6y = x + 18

Replacing x with the result of the 1st equation:

6y = (6 - 2y) + 18

6y = 6 - 2y + 18

6y + 2y = 18 + 6 (Adding 2y at both sides)

8y = 24

y = 24/8 = 3 (Dividing  by 8 at both sides)

Now we can find out the value of x:

x + 2y = 6

x + 2 * 3 = 6

x = 6 - 6 (Subtracting 6 at both sides)

x = 0

3. Let's prove that x = 0 and y = 3 in the 2nd equation:

6y = x + 18

6 * 3 = 0 + 18

18 = 18

We proved that x = 0 and y = 3 are correct.

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