Esaca una bola de billar al azar de una caja que contiene 15 bolas de billar numeradas del 1 al 15 y se registra el número obtenido con la letra "n". encuentra la probabilidad de que el número obtenido "n" de la bola de billar sacada de la caja sea mayor a 10 y "n" sea par.

P = 2/7 = 0.2857 or 28.57%

Step-by-step explanation:

First, we know that we have 15 balls, and we need to know which one of them is pair, and higher than 10.

So, we first need to calculate the probability that the obtained number is pair.

The pair numbers are 2,4,6,8,10,12,14

We have 7 numbers out of 15 ---> P(B) = 7/15

From those numbers, only two of them are higher than 10, which are 12 and 14, so: P(A|B) = 2/15

To get the probability to get a number higher than 10 and pair:

P(A/B) = P(A|B) / P(B)

P(A/B) = 2/15 / 7/15 = 2/7 = 0.2857

To get the percentage: 0.2857 * 100 = 28.57%.

sorry man i accidentally pressed yes my bad

step-by-step explanation: