When purchased, the height of a japanese maple sapling is 14 inches. the tree is expected to grow 2.5 inches each month. which function models the relationship between the height of the tree f(m) and the number of m months of growth? a) f(m) = 2.5m b) f(m) = 2.5m + 14 c) f(m) = 14m + 2.5 d) f(m) = 2.5m − 14

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation:

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.