There is 1 red gumdrop and 4 green gumdrops in a small jar. also, 2 pieces of butterscotch candy and 3 pieces of cinnamon
candy are in another jar. if craig draws one piece of candy from each jar without looking, what's the probability that he will
get a red gumdrop and a piece of butterscotch candy?

The probability that he will get a red gumdrop and a piece of butterscotch candy is 2/25

Step-by-step explanation:

The path to find the answer is to find the probability of both things happening  and then multiply them. First, there is 1 red gumdrop and 4 green gumdrops in a jar. There are 5 gumdrops total so the probability of choosing a red one is 1/5. Next, there are 2 pieces of butterscotch candy and 3 pieces of cinnamon candy in another jar. There are 5 pieces of candy total so the probability of choosing a piece of butterscotch candy is 2/5. Finally multiply the two probabilities: 1/5 * 2/5 = 2/25.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.