An event sold $608 worth of tickets. adult tickets cost $11 and children's tickets cost $6. if 68 tickets were sold, how many were adult tickets and how many were children's tickets?

There were 40 adult tickets and 28 children's tickets

Step-by-step explanation:

Let x represent the number of adult tickets sold.

Let y represent the number of children's tickets sold.

An event sold $608 worth of tickets adult tickets cost $11 while children's tickets cost $6. It means that

11x + 6y = 608 - - - - - - 1

If 68 tickets were sold, it means that

x + y = 68

Substituting x = 68 - y into equation 1, it becomes

11(68 - y) + 6y = 608

748 - 11y + 6y = 608

- 11y + 6y = 608 - 748

- 5y = 140

y = 140/5 = 28

x = 68 - y = 68 - 28

x = 40

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195

b. 153 students do not participate in sports and seventy-five 12th graders were surveyed