Bara research group conducted a survey about church attendance. the survey respondents were asked about their church attendance and asked to indicate their age. use the sample data to determine whether church attendance is independent of age. using a .05 level of significance. excel file: data12-31.xlsassb12h_ch12_12.31.gif the p-value is - select your answer -between .025 and .05between .05 and .025between .015 and .045item 1 .what is your conclusion? - select your answer -conclude church attendance is not independent of age. conclude church attendance is independent of age. item 2what conclusion can you draw about church attendance, as individuals grow older?

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation:

answer: 800

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.