Aroulette wheel has the numbers 1 through 36, 0, and 00. a bet on three numbers pays 11 to 1 (that is, if you bet $1 and one of the three numbers you bet comes up, you get back your $1 plus another $11). how much do you expect to win with a $1 bet on three numbers?

You are expected to lose $0.05 (or win -$0.05)

Step-by-step explanation:

Since the roulette wheel has the numbers 1 through 36, 0, and 00, there are 38 possible outcomes.

In this bet, you are allowed to pick 3 out of the 38 numbers. Thus, your chances of winning (P(W)) and losing (P(L)) are:

The expected value of the bet is given by the sum of the product of each outcome pay by its probability. Winning the bet means winning $11 while losing the bet means losing $1. The expected value is:

Therefore, with a $1 bet, you are expected to lose roughly $0.05

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

answer: 12

step-by-step explanation:

because yes