99 points will give no fake answers!
a computer programmer has a 35% chance of finding a bug in any given program. what is the probability that she finds a bug within the first three programs she examines?
a) 0.15
b) 0.27
c) 0.59
d) 0.73

a fair coin is flipped multiples times until it lands on heads. if the probability of landing on heads is 50%, what is the probability of first landing on heads on the fourth attempts?
a) 0.625
b) 0.0625
c) 0.500
d) 0.382

1.

Chance of finding a bug = 0.35

Chance of not finding a bug = 1 - 0.35 = 0.65

Probability of finding a bug in the first 3 programs =

Probability of not finding a bug in 2 out of the 3 and finding a bug in 1.:

0.65^2 * 0.35 = 0.147 = 0.15

Answer is A.

2.

Probability of heads = 0.50

Probability of tails = 0.50

Probability of heads on the fourth attempt = tails x tails x tails x heads = 0.5 x 0.5 x 0.5 x 0.5 = 0.0625

The answer is B.

answer: give more info

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.