Acounty clerk wants to estimate the proportion of voters who will need special election facilities.
suppose a sample of 400 voters was taken.
if 150 need special election facilities, what is the upper confidence limit (ucl) for the 90% confidence interval for the population proportion of voters who will need special election facilities?
round your answer to 3 decimal places.

The upper confidence limit for the 90% confidence interval would be 0.415.

Step-by-step explanation:

Since we have given that

n = 400

x = 150

So,

At 90% confidence interval, z = 1.645

So, margin of error would be

So, the upper limit would be

Hence, the upper confidence limit for the 90% confidence interval would be 0.415.

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day