Suppose the cost c(x), to build a football stadium of x thousand square feet is approximated by c(x) = 7,250,000/ x + 60 . how many square feet was the stadium if the cost of the stadium was $8,000?

Step-by-step explanation:

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/x + 60. Given the function, we can substitute values for x to determine the cost of a particular size of stadium or we can substitute values for C(x) to determine the number of square feet.

if the cost of the stadium was $8,000, the, we would determine the size of the stadium, x by substituting x $8,000 for C(x). It becomes

8000 = 7250,000/x + 60

8000 - 60 = 7250000/x

7940 = 7250000/x

7940x = 7250000

x = 7250000/ 7940

x = 913 ft^2

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490