Three pipes a and b and c can fill a swimming pool in 6 hours. after working on it together for 2 hours, c is closed and a and b finish the remaing work in 7 hours. find the time taken by alone to fill the swimming pool.

The pipe C alone can fill the tank in 14 hours .

Step-by-step explanation:

Given as :

The three pipes a , b , c can fill the pipes in 6 hours

They work for 2 hours

After that c pipe is close and a , b finish remaining work

Now, According to question

In 1 hour pipes ( a + b + c ) fill of the tank

∴ In 2 hour pipes ( a + b + c ) fill =   of the tank

Remaining ( 1 -  ) =  part is filled by pipes a and b in 7 hours

∴ The whole tank is filled by a and b in 7 × =   hours

∴ In 1 hour pipes A and b fill the tank in hours

∴ In 1 hour pipes C alone can fill the tank in - hours

Or,  In 1 hour pipes C alone can fill the tank in =  

Or, In 1 hour pipes C alone can fill the tank in 14 hours

Hence The pipe C alone can fill the tank in 14 hours . Answer

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.