The length of a rectangle is four times the width. the perimeter of the rectangle is 45 inches. write a system of equations that represents this problem. what is the area of the rectangle?

Let l be the length and w the width of the rectangle.

P as the perimeter and A as the area.

length of a rectangle is four times the width:

w = w

l = 4w

System of equation : 2l + 2w = P

Substitute:

2(4w) + 2w = 45

8w + 2w

10w = 45

w = 45 / 10

w = 4.5

Solve for l:

l = 4w

l = 4(4.5)

l = 18

Area:

A = lw

A = 18(4.5)

A = 81 in²

area =81  square inches

Step-by-step explanation:

width =w

lenght= 4w

2w + 2(4w)=45

10w=45

w=4.5

l= 4.5(4) = 18

4.5+4.5 +18+18 = 45

Area = l*w

4.5*18 = 81

Area= 81 square inches

21

jk it's 20

step-by-step explanation: