Recall that the stopping distance of a vehicle traveling at v miles per hour is din feet)
round all answers to the nearest hundredth, where necessary
a. what is the stopping distance for a car traveling at 70 mph? do not round your answer.
feet
b. if it takes you 130 feet to come to a complete stop, how fast was your car traveling?
mph
c. convert 70 miles per hour to feet per second
feet per second
d. you are traveling with 70 mph, and there is an accident in front of you. you jump on the brake but your
reaction time is 0.9 seconds. what is the stopping distance?
feet
e. brakes do not engage instantaneously either. there is an additional time required for the pedal to depress and
for the brakes to engage in an emergency, a reasonable estimate is 0.2 second. find the additional stopping
distance resulting from this delay in the engagement of the brakes.
additional feet
f. what is the total stopping distance including the results from parts (d) and (e)?

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: