[50+25 points + the brainliest]

if sin θ = 3/5, and lies in quadrant ii, what are the exact values of sin 2θ, cos 2θ , and tan 2θ ?

you in advance!

sin2θ = -24/25

cos2θ = 7/25

tan2θ =  -24/7

Step-by-step explanation:

sinθ = 3/5

θ is in Quadrant II. So 2θ is in Quadrant III or IV. So sin2θ is negative. Nothing can be said about cos and tan yet.

sin135 = 0.707 > 3/5.

So θ > 135.

2θ lies in Quadrant IV. So cos2θ is positive and tan2θ is negative.

cosθ = √(1 - sin²θ)

        = -4/5

sin2θ = 2sinθcosθ = 2x(3/5)x(-4/5) = -24/25

cos2θ = 1 - 2sin²θ = 1 - 2x(3/5)² = 7/25

tan2θ = sin2θ/cos2θ = -24/7

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.