Mathematics, 02.12.2019 04:31 Bradgarner772
Length of rectangle is 5yd more than double the width, and the area of the rectangle is 42yd. find the dimension of the rectangle.
Answers: 2
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For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠[tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
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Length of rectangle is 5yd more than double the width, and the area of the rectangle is 42yd. find t...
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