How to solve : 16=2t + 0.25 t``squar

The solutions of the equation are t = 4(√5 + 1) or 4(√5 - 1).

Step-by-step explanation:

We have to solve the given quadratic equation of single variable t.

The equation is 16 = 2t + 0.25t²

⇒ 0.25t² + 2t - 16 = 0

⇒ 25t² + 200t - 1600 = 0 {Multiplying both sides with 100}

⇒ 25t² + 200t + 400 - 400 - 1600 = 0

⇒ (5t + 20)² - 2000 = 0

⇒ (5t + 20)² - (20√5)² = 0

⇒ (5t + 20 + 20√5)(5t + 20 - 20√5) = 0

So, (5t + 20 + 20√5) = 0 or, (5t + 20 - 20√5) = 0

⇒ (t + 4 + 4√5) = 0 or, (t + 4 - 4√5) = 0

⇒ t = - 4(1 + √5) or, t = 4(√5 - 1) (Answer)

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step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm