9) an aircraft carrier left hawaii and traveled
toward dry dock at an average speed of 15
mph. a submarine left two hours later and
traveled in the opposite direction with an
average speed of 15 mph. find the
number of hours the submarine needs to
travel before the vessels are 300 mi. apart.

The Time taken by submarines to travel before the vessel is 11 hours

Step-by-step explanation:

Given as :

The average speed of aircraft carrier = 15 mph

The average speed of submarine = 15 mph

The distance between them = 300 mile

The time taken by aircraft = T hour

The time taken by submarine = T + 2  hour

Now, Speed =

So, Distance =  Speed × Time

Now,

300 miles = 15 × T + 15 × ( T + 2)

Or, 300 = 15 T + 15 T + 30

or, 300 - 30 = 30 T

Or, 270 = 30 T

∴ T =

I,e T = 9 hours

So, T + 2 = 9 + 2 = 11 hours

Hence The Time taken by submarines to travel before the vessel is 11 hours Answer

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)