Mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3) represents linear function. is she correct. explain your reasoning

The graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function

Step-by-step explanation:

Mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3)

Now, the line joining (-3,-3) and (-3,0) has slope = = ∞

Again, the line joining (-3, 0) and (-3,3) has slope = = ∞

Therefore, both the lines are parallel to y-axis and has a common point (-3,0). {Since, tan Ф = ∞, ⇒ Ф = 90°}

So, the graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function as the graph represents a vertical line parallel to y-axis. (Answer)

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

answer: it's d

step-by-step explanation: