R=ht²/2 - 2vt - 2c solve the equation for v

v=1/4ht-c/t-r/2t

Step-by-step explanation:

r=ht^2/2-2vt-2c

2vt=ht^2/2-2c-r

2vt=(1/2)ht^2-2c-r

vt=[(1/2)/2]ht^2-2/2c-r/2

vt=1/4ht^2-c-r/2

v=(1/4ht^2)/t-c/t-(r/2)/t

v=1/4ht-c/t-r/2t

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.