Flying against the wind, an airplane travels 5760 kilometers in 6 hours. flying with the wind, the same plane travels 6300 kilometers in 5 hours. what is the rate of the plane in still air and what is the rate of the wind?

Step-by-step explanation:

Let the speed of plane be p and speed of wind be w.

Flying against the wind, an airplane travels 5760 kilometers in 6 hours.

Here

            Speed = (p-w) kmph

            Time = 6 hours

            Distance = 5760 kmph

            Distance = Speed x Time

            5760 = (p-w) x 6

               p-w = 960 eqn 1  

Flying with the wind, the same plane travels 6300 kilometers in 5 hours.

Here

            Speed = (p+w) kmph

            Time = 5 hours

            Distance = 6300 kmph

            Distance = Speed x Time

            6300 = (p+w) x 5

               p+w = 1260 eqn 2    

eqn 1 + eqn 2

                p-w + p +w =  960 + 1260

                  2p = 2220

                    p = 1110 kmph

Substituting in eqn 2

                1110 + w = 1260

                         w = 150 kmph

Speed of plane = 1110 kmph

Speed of wind = 150 kmph

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6