Astone is thrown straight up from the edge of a roof, 775 feet above the ground, at a speed of 16 feet per second. a. remembering that the acceleration due to gravity is −32ft/sec2, how high is the stone 4 seconds later?

435 ft off the ground

Step-by-step explanation:

Use

s = u t + 1/2 at²

Here

s = distance traveled

u = initial velocity

t = time

a = acceleration

putting values in equation

  = 16 *4 +1/2 32 *16

  =  64 + 256

  = 320

So the stone is

775 - 320 = 435 ft off the ground

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.