The frequency of vibration of a piano string varies directly as the square root of the tension on the string and inversely as the length of the string. the middle a string has a frequency of 440 vibrations per second. find the frequency of a string that has 1.25 times as much tesnsion and is 1.2 times as long.

  about 409.946 Hz

Step-by-step explanation:

The multiplier of frequency is (√(tension multiplier))/(length multiplier), so is ...

  (√1.25)/1.2 = (5/12)√5 ≈ 0.931695

So, the longer, tighter string will have the lower frequency of about ...

  0.931695×440 Hz ≈ 409.946 Hz

stethere all not eveanp-by-step explanation:

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.