In a certain corporation, there are 300 male employees and 100 female employees. it is known that 20% of the male employees have advanced degrees and 40% of the females have advanced degrees. if one of the 400 employees is chosen at random, what is the probability this employee has an advanced degree or is female? a. 1/20b. 1/10c. 1/5d. 2/5e. 3/4

A. 1/2

Step-by-step explanation:

P(AD or F)  = probability of a person having an advanced degree + probability

                     of a person being female

                   = (20% of 300 + 40% of 100)/400 + 100/400

                   = (60+40)/400  + 100/400

                   =  1/2

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

it is x=-4

step-by-step explanation: