Use synthetic division to divide 6x^3-10x^2+20 by x+1

quotient:

remainder:

the quotient is 6x^2 - 16x + 16, and the remainder is just 4

Step-by-step explanation:

The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}.  Division by the binomial x + 1 requires that we use -1 as the divisor.  The synthetic division setup becomes:

-1   /    6    -10    0    20

                 -6    16   -16

          6     -16   16       4

Taking the coefficients {6, -16, 16}, we write the quotient as

6x^2 - 16x + 16, and the remainder as just 4.

what's that