High tech, inc randomly tests its employees about company policies. last year in the 400 random tests conducted, 14 employees failed the test. a. develop a 99% confidence interval for the proportion of applicants that fail the test. (round answers to 3 decimal places) confidence interval for the proportion mean is between and . would it be reasonable to conclude 5% of the employees cannot pass the employee test? yes or no

Confidence interval for the proportion mean is between 0.0113 and 0.0587. B. Yes, it is reasonable to conclude that 5% of the employees cannot pass the employee test.

Step-by-step explanation:

We have a large sample size of n = 400 random tests conducted. Let p be the true proportion of employees who failed the test. A point estimate of p is , we can estimate the standard deviation of as . A confidence interval is given by , then, a 99% confidence interval is , i.e., , i.e., (0.0113, 0.0587). is the value that satisfies that there is an area of 0.005 above this and under the standard normal curve. B. Yes, it is reasonable to conclude that 5% of the employees cannot pass the employee test, because this inverval contain 0.05.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .