Given the following information about two loaded die, what is the p(5) on die 2? die 1p(1) = 0.5 p(4) = 0.25 p(6) = 0.25 die 2p(2) = 0.3 p(3) = 0.25 p(5) = ? ?

0.45

Step-by-step explanation:

Die 1 is loaded so that only 1, 4, and 6 are possible.

P(1) + P(4) + P(6) = 0.5 + 0.25 + 0.25 = 1

Similarly, Die 2 is loaded so that only 2, 3, and 5 are possible.

P(2) + P(3) + P(5) = 1

0.3 + 0.25 + P(5) = 1

P(5) = 0.45

i'm not sure i quite understand, could you provide more information?

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6