Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. from the shipment you take a random sample of 25. when sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. in our sample of 25 we reject the entire shipment if x> 5. what is the probability of rejecting the entire shipment?

0.2425 or 24.25%

Step-by-step explanation:

If the shipment of 400 components contains 68 defective and, we can estimate the probability of selecting a defective components as

68/400 = 0.17

Now, we have a binomial experiment of 25 trials and we want to compute the probability that more than 5 trials are “success” (defective component)

P(X>5) = 1 - P(X≤ 5)

Since  

1 - P(X≤ 5) = 1 - (P(X=0) + P(X=1) + P(X=3) + P(X=4) + P(X=5) =  

55? i think maybe

step-by-step explanation:

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet