Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{align ed} & -9y+4x - 20=0 & -7y+16x-80=0 \end{aligned} −9y+4x−20=0 −7y+16x−80=0 what is the value of x and y

Step-by-step explanation:

Subtract 4 times the first equation from the second:

  (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)

  29y = 0 . . . . . simplify

  y = 0 . . . . . . . .divide by 29

  4x -20 = 0 . . . . substitute 0 for y in the first equation

  x -5 = 0 . . . . . .divide by 4

  x = 5 . . . . . . . . add 5

The solution to this system is (x, y) = (5, 0).

the answer is 15% decrease

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it