Taxi company has three cabs. calls come in to the dispatcher at times of a poisson process with rate 2 per hour. suppose that each requires an exponential amount of time with mean 20 minutes, and that callers will hang up if they hear there are no cabs available. (a) what is the probability all three cabs are busy when a call comes in? (b) in the long run, on the average how many customers are served per hour?

your answer is a

step-by-step explanation:

plzplzplzplzplz mark brainliest i need it.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

77

step-by-step explanation:

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6