Plz

25 pts with brainlest

solve |x| + 7 < 4.

{x | x < -11 or x > -3}

{x | -3 < x < 3}

ø

No solution.

You can also write this as the empty set.

The symbol for empty set is ∅.

The problem:

Solve |x|+7<4

Step-by-step explanation:

|x|+7<4

Subtract 7 on both sides to get the term containing the | | by itself:

|x|+7-7<4-7

|x|+(7-7)<4-7

Simplify:

|x|<-3

The thing is this will never happen for any x since there is no positive number  less than -3. Also 0 is not less than -3. All positive numbers or 0 are greater than any given negative number.

| | will always produce a positive or 0 output.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!