Alemming runs from point a to a cliff at 4m/s, jumps over the edge at b and falls to c at average speed of 25 m/s. if the total distance from a to c is 500m and the time taken for the journey is 41 seconds, find the height bc of the cliff.

The height BC of the cliff is 400 m

Step-by-step explanation:

Let the distance between the point A to the cliff at B is x meters and the height BC is y meters.

So, x + y = 500 ....... (1)

⇒ 4x + 4y = 2000 .......... (2)

Now, at the speed of 4 m/s the time of travel from points A to B is sec. and at a rate of fall of 25 m/s the times taken to fall from B to C will be sec.

So, from the conditions given we can write  

....... (3)

⇒ 25x + 4y = 4100 ........ (4)

Now, solving equations (2) and (4) we get  

21x = 2100

⇒ x = 100 m

So,  from equation (1) we can write y = (500 - 100) = 400 m.

Therefore, the height BC of the cliff is 400 m (Answer)

too hard the other guy did it

step-by-step explanation: