We will prove the following identity involving the multinomial coefficient: n n1 n − n1 n2 n − n1 − n2 n3 . . n − pd−1 i=1 ni nd = n! n1! n2! n3! . nd! recall that pd i=1 ni = n. (a) prove this identity algebraically. (b) prove this identity using a combinatorial argument.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

answer: 0.1,0.85

step-by-step explanation:

explanation:

step-by-step explanation: