Kari and samantha have determined that their water-balloon launcher works best when they launch the balloon at an angle within 3 degrees of 45 degrees. which equation can be used to determine the minimum and maximum optimal angles of launch, and what is the minimum angle that is still optimal?

The equation which can be used to determine the minimum and maximum optimal angles of launch is:

                |x – 45| = 3

and the  minimum angle that is still optimal is:

                             42 degrees.

Let x be the optimal angle by which the balloon is launched.

Also, it is given that the  they launch the balloon at an angle within 3 degrees of 45 degrees.

i.e. the range at which the angle is launched lie between 3 degree less than 45 degree and 3 degree more than 45 degree.

Hence, the equation that will represent this relationship is:

            |x-45|=3

Hence, on solving for the maximum value we have:

and the smallest optimal angle is given by:

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .