Randall wants to mix 44 lb of nuts worth $1 per lb with some nuts worth $9 per lb to make a mixture worth $8 per lb. how many pounds of $9 nuts must he use?

38.5 pounds

Step-by-step explanation:

Let pounds of $1 nuts used be "x"

Let pounds of $9 nuts used be "y"

44 lb of nuts in total, so we can say:

x + y = 44

or

x = 44 - y

Now, the mixture of 44 lb nuts would be worth $8, so we can write:

1x + 9y = 8(44)

x + 9y = 352

We replace this with the 1st equation (x = 44 - y) and find the value of "y":

x + 9y = 352

44 - y + 9y = 352

8y = 352 - 44

8y = 308

y = 308/8

y = 38.5

So, we need to mix 38.5 pounds of $9 nuts

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2