Two bicycles are traveling along perpendicular roads. bicycle a is traveling due east at 4 mi/hr, and bicycle b is travelling due north at 6 mi/hr. at noon, when bicycle a reaches the intersection, bicycle b is 9 mi away and moving toward the same intersection if t is the number of hours after noon, the bicycles are closest together when t isa. 0b. 27/26c. 9/5d. 3/2e. 14/13

Step-by-step explanation:

Given

speed of cyclist A is

speed of cyclist B is

At noon cyclist B is 9 mi away

after noon Cyclist B will travel a distance of 6 t and cyclist A travel 4 t miles in t hr

Now distance of cyclist B from intersection is 9-6t

Distance of cyclist A from intersection is 4 t

let distance between them be z

Differentiate z w.r.t time

Put

therefore

b. the decimal could be two-tenths.

step-by-step explanation:

i pretty sure it is