If you are dealt 5 cards from a shuffled deck of 52 cards, find the probability of getting two queens and three kings.
the probability is
nothing.
(round to six decimal places as needed.)

The probability of getting two queens and three kings is

Given that, you are dealt five cards from a shuffled deck of 52 cards  

We have to find the probability of getting two queens and three kings  

Now, we know that, in a deck of 52 cards, we will have 4 queens and 4 kings.

Probability of first queen:

Probability of second queen:

Here we used 3 for favourable outcome, since we already drew 1 queen out of 4

And now number of outcomes = 52 – 1 = 51

Probability for first king:

Here favourable outcomes = 4

And now number of outcomes = 51 – 1 = 50

Probability for second king:

Here favourable outcomes = 3, since we already drew 1 king

And now number of outcomes = 50 - 1 = 49

Probability for third king:

Here favourable outcomes = 2, since we already drew 2 king

And now number of outcomes = 49 - 1 = 48

Now the total probability of getting 2 queens and 3 kings from a shuffled deck of cards is:

Hence, the probability is

42

step-by-step explanation:

256/6=42

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this