What is the equation in point slope form of the line that goes through the points (-4,-2) and(-6,16)

y+2=-9(x+4)

Step-by-step explanation:

Point Slope Form: y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=(y2-y1)/(x2-x1)=(16-(-2))/(-6-(-4))=(16+2)/(-6+4)=18/-2=-9

So the slope is -9,

y-(-2)=-9(x-(-4))

y+2=-9(x+4)

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later

d

step-by-step explanation:

the two points from this line are   (0,4)   & (2,-2)

we can call

now, lets find the slope (m):

now finding b (the y intercept). this is the point at the y-axis where the line cuts the axis. looking at the graph, it is y = 4. so the point is 4. hence b = 4

the slope-intercept form is given by  

putting the points, we have:

d is the correct answer.