The angle of depression from the top of one building to the foot of a building across the street is 53°. the angle of depression to the top of the same building is 19°. the two buildings are 80 feet apart. what is the height of the shorter building?

78.64 feet

Step-by-step explanation:

Refer the attached figure

Height of the tall building = AC

The angle of depression from the top of one building to the foot of a building across the street is 53°. i.e.∠ADC = 53°

The angle of depression to the top of the same building is 19°.i.e.∠AEB = 19°

Height of small building = ED

The two buildings are 80 feet apart i.e. CD =BE= 80 feet

In ΔABC

In ΔABE

AC - AB = BC

106.16-27.52=BC

78.64=BC

So, BC = ED = 78.64 feet

Hence the height of the shorter building is 78.64 feet

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof