Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. if one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be filled?
a) 6
b) 9
c) 12
d) 27
e) 48

b) 9

Step-by-step explanation:

Given: Three machines  operating independently, simultaneously, and at the same constant rate can fill a certain production order in hours.

To Find: If one additional machine were used under the same operating conditions, in how many fewer hours of simultaneous operation could the production order be filled.

Solution:

Let  the time taken by one machine to fill a certain production alone be

Time taken when three machine operate independently and simultaneously

Let time taken when one additional machine is used

Time when when one additional machine is used

it takes when one additional machine is used

Now,

fewer hours taken when one additional  machine is used

in fewer hours of simultaneous operation the production order can be filled if one additional machine is used

Hence option b) is correct.

the total estimated nappy use.=10,500,000

step-by-step explanation:

given that on an average the average baby uses 3528 napkins.

in a particular year 2014, the number of births were 299697 in new south wales.

rounding off the number of births to the nearest hundred thousand we have

no of birtsh = 300000

also rounding off the average usage to nearst thousand we get

average use of a baby = 3500

hence total number of nappy estimated to be used = 3500x300000

= 10,500,000

answer is 10,500,000 nappies

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.