Agame spinner has eight equal sections: three sections numbered 1, one section numbered 2, and four sections numbered 3. the spinner is spun twice. what is the probability that the sum of the two spins will be five?

The required probability is or 0.125

Step-by-step explanation:

Consider the provided information.

The spinner is spin twice and we want the sum should be 5.

We can get 5 if first spin gives us 2 and second spin gives 3.

Or we can get 5 if first spin gives us 3 and second spin gives 2.

There are 8 section out off which Three sections numbered 1, one section numbered 2, and four sections numbered 3.

The probability of getting 2 is

The probability of getting 3 is

Now, the probability that the sum of the two spins will be five is:

Hence, the required probability is or 0.125

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step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)