Aplane travels speed at 225 mph in still air. flying with tailwind, the plane is clocked over distance of 875 miles. flying against headwind, it takes 1 hour longer to complete the return trip. what is the wind velocity?

The wind speed is 28.466 mi/h

Step-by-step explanation:

Let's call Vs=225mi/h the plane speed in still air. Let's have X=875 mi the distance traveled

We'll also call Vw the wind speed. In the first flight, the plane goes with a speed of Vs+Vw.

The return trip is made flying against a headwind with a speed of Vs-Vw

The time taken to travel X miles with a tailwind is

The time taken to travel X miles with a headwind is

We know because the return trip is 1 hour longer. Then we have

Multiplying by (Vs+Vw)(Vs-Vw)

Replacing the values of X=875 and Vs=225 we reach a second-degree equation

Which has the following roots:

Vw=28.466, Vw=-1778.466

We take the positive root and conclude

The wind speed is 28.466 mi/h

Note: We can easily check that the first time is 3.45h and the second time is 4.45h.

pls ask

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b