Charlie is watching hot air balloons. balloon a has risen at a 60° angle. balloon b has risen at an 82° angle. if the distance from balloon a to the ground is 1,400 feet, how far is balloon b from balloon a? round your answer to the nearest whole number.

The distance of balloon B from balloon A is 4351 feet  .

Step-by-step explanation:

Given as :

The angle made by balloon A from ground = 60°

The angle made by balloon B from ground = 82°

The height of balloon A from the ground = 1400 feet

The height of balloon B from the ground = 1400 feet + h feet

Let the distance between Charlie and ground = x feet

Now, From figure

In triangle OCA

Tan 60° =

or, Tan 60° =

Or, x =

i.e x =

∴  x = 808.314 feet

In Triangle OCB

Tan 82° =

or, Tan 82° =

Or, 1400 + h = x × Tan 82°

Or, 1400 + h = 7.115 × x

Or,  1400 + h = 7.115 × 808.314

Or,  1400 + h = 5751.154

or, h = 5751.154 - 1400

∴   h = 4351.154 feet

So The distance of balloon B from balloon A is 4351 feet  . Answer

false.

step-by-step explanation:

false.

cavalieri's principle makes that statement about the volumes, not about the areas.

its kind of blurry. can you put a clearer pic?

step-by-step explanation: