Ahospital/surgical expense policy was purchased for a family of four in march of 2013. the policy was issued with a $500 deductible and a limit of four deductibles per calendar year. two claims were paid in september 2013, each incurring medical expenses in excess of the deductible. two additional claims were filed in 2014, each in excess of the deductible amount as well. what would be this family's out-of-pocket medical expenses for 2013?

The answer is $1000.

Step-by-step explanation:

The policy was issued with a $500 deductible and a limit of four deductibles per calendar year.

As given that two claims were paid in September 2013, each incurring medical expenses in excess of the deductible.

So, the family's out-of-pocket medical expenses for 2013 will be :

dollars

As the limit was up to 4 deductibles in a calendar year, and in 2013, there were 2 claims, so that sums up to be $1000.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

45

step-by-step explanation:

to find a percentage, add a decimal in front and multiply it by the other number.

.25 times 180= 45