Kayson is looking at two buildings, building a and building b, at an angle of elevation of 40°. building a is 120 feet away, and building b is 60 feet away. which building is taller and by approximately how many feet?

Building A is taller by approximately 50.346 feet

Step-by-step explanation:

The situation is pictured in the image below, being x the distance between Kayson and any of the buildings and y their height

One basic relation in a right triangle is:

Thus, the height is

For the building A x=120 feet, so

For the building A x=60 feet, so

We can see the building A is taller by approximately 100.692-50.346 = 50.346 feet

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

probably the last option

step-by-step explanation: