Asap i need with law of cosines how the heck do you find the degree for #2

130.54°

Step-by-step explanation:

The formula for law of cosines is c^2= a^2+ b^2 -2ab cos(C),

a,b, and c are the sides of the triangle. C is the angle opposite to the side c.

To solve this problem add the given values into the formula, and solve for C.

10^2=5^2+ 6^2- 2(5)(6) cos(C)

100=25+36 - 2(5)(6) cos(C)

100=25+36 -60 cos(C)

100=61 -60 cos(C)

39= -60 cos(C)

cos^-1 (-39/60)= C

130.54°=C

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation: